If 2 bulbs rated 2.5 W – 110 V and 100 W – 110 V are connected in series to a 220 V supply then
Text Solution
Verified by ExpertsThe correct answer is:
A
R 2.5W = 
, R 100W = 
⇒ R 2.5 > R 100 .
In series current passes through both bulb are same
P 2.5 = i 2 R 2.5 , P 100 = i 2 R 100
P 2.5 > P 100 due to R 2.5 > R 100
Therefore 2.5 W bulb will fuse first.
R 2.5W = 
, R 100W = 
⇒ R 2.5 > R 100 .
P 2.5 = i 2 R 2.5 , P 100 = i 2 R 100
P 2.5 > P 100 due to R 2.5 > R 100
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